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[SPAM] Re: [obm-l] PASSEIO
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Acredito que h=E1 apenas um erro na resolu=E7=E3o abaixo:
Em vez C(4,2), o correto =E9 A(4,2). Usar combina=E7=E3o =E9 inadequado, =
pois, fazendo a =E1rvore de possibilidades, teremos 1 dos 4 motoristas =
que ir=E1 apenas em 1 dos 2 carros e outro motoristas que ir=E1 apenas =
em 1 carro tamb=E9m. Veja o exemplo:
C(4,2) =3D 6
Sendo A e B os carros e 1,2,3 e 4 os motoristas poss=EDveis, temos:
A=3D=3D=3D=3D=3D=3D=3D=3D=3DB
1 2
1 3=20
1 4=20
2 3=20
2 4=20
3 4
Veja que todos, exceto 1 e 4, podem dirigir os carros A e B. Ent=E3o =E9 =
mais apropriado usar Arranjos mesmo, pois a ordem importa !=20
=20
----- Original Message -----=20
From: Andre Araujo=20
To: obm-l@mat.puc-rio.br=20
Sent: Monday, July 09, 2007 1:21 PM
Subject: Re: [obm-l] PASSEIO
Akron,
voc=EA escolhe primeiro os motoristas, C(4,2), depois permuta os seis =
lugares restantes, 6!. Assm o n=FAmero total de modos =E9: C(4,2) * 6! =
=3D 4320.
AA.
Em 09/07/07, arkon <arkon@bol.com.br> escreveu:
Pessoal, como resolvo esta:
Um grupo de 8 jovens pretende sair para um passeio em dois carros =
(cada um com capacidade para 4 pessoas). Apenas 4 delas dirigem. O n=BA =
de modos deles escolherem seus lugares nos dois carros =E9 igual a :=20
a) 10.080. b) 8.640. c) 4.320. d) 1.440. e) 720.
Desde j=E1 obrigado=20
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charset="iso-8859-1"
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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META http-equiv=3DContent-Type content=3D"text/html; =
charset=3Diso-8859-1">
<META content=3D"MSHTML 6.00.2900.2180" name=3DGENERATOR>
<STYLE></STYLE>
</HEAD>
<BODY bgColor=3D#ffffff>
<DIV><FONT face=3DArial size=3D2>Acredito que h=E1 apenas um erro na =
resolu=E7=E3o=20
abaixo:</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2>Em vez C(4,2), o correto =E9 A(4,2). =
Usar combina=E7=E3o=20
=E9 inadequado, pois, fazendo a =E1rvore de =
possibilidades, teremos 1 dos=20
4 motoristas que ir=E1 apenas em 1 dos 2 carros e outro motoristas que =
ir=E1 apenas=20
em 1 carro tamb=E9m. Veja o exemplo:</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>C(4,2) =3D 6</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2>Sendo A e B os carros e 1,2,3 e 4 =
os=20
motoristas poss=EDveis, temos:</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV><FONT face=3DArial =
size=3D2>A=3D=3D=3D=3D=3D=3D=3D=3D=3DB</FONT></DIV>
<DIV><FONT face=3DArial=20
size=3D2>1 &nb=
sp; 2</FONT></DIV>
<DIV><FONT face=3DArial=20
size=3D2>1 &nb=
sp; 3=20
</FONT></DIV>
<DIV><FONT face=3DArial=20
size=3D2>1 &nb=
sp; 4=20
</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>2 =20
&=
nbsp; =20
3 </FONT></DIV>
<DIV><FONT face=3DArial=20
size=3D2>2 &nb=
sp; 4=20
</FONT></DIV>
<DIV><FONT face=3DArial=20
size=3D2>3 &nb=
sp; 4</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2>Veja que todos, exceto 1 e 4, podem =
dirigir os=20
carros A e B. Ent=E3o =E9 mais apropriado usar Arranjos mesmo, pois a =
ordem importa=20
! </FONT></DIV>
<DIV> </DIV>
<BLOCKQUOTE=20
style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
<DIV style=3D"FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV=20
style=3D"BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: =
black"><B>From:</B>=20
<A title=3Dalsdearaujo@gmail.com =
href=3D"mailto:alsdearaujo@gmail.com">Andre=20
Araujo</A> </DIV>
<DIV style=3D"FONT: 10pt arial"><B>To:</B> <A =
title=3Dobm-l@mat.puc-rio.br=20
href=3D"mailto:obm-l@mat.puc-rio.br">obm-l@mat.puc-rio.br</A> </DIV>
<DIV style=3D"FONT: 10pt arial"><B>Sent:</B> Monday, July 09, 2007 =
1:21 PM</DIV>
<DIV style=3D"FONT: 10pt arial"><B>Subject:</B> Re: [obm-l] =
PASSEIO</DIV>
<DIV><BR></DIV>Akron,<BR><BR>voc=EA escolhe primeiro os motoristas, =
C(4,2),=20
depois permuta os seis lugares restantes, 6!. Assm o n=FAmero total de =
modos =E9:=20
C(4,2) * 6! =3D 4320.<BR><BR>AA.<BR><BR>
<DIV><SPAN class=3Dgmail_quote>Em 09/07/07, <B =
class=3Dgmail_sendername>arkon</B>=20
<<A href=3D"mailto:arkon@bol.com.br">arkon@bol.com.br</A>>=20
escreveu:</SPAN>
<BLOCKQUOTE class=3Dgmail_quote=20
style=3D"PADDING-LEFT: 1ex; MARGIN: 0pt 0pt 0pt 0.8ex; BORDER-LEFT: =
rgb(204,204,204) 1px solid">
<DIV style=3D"FONT-SIZE: 12px; FONT-FAMILY: verdana,arial">
<DIV>
<P style=3D"MARGIN: 0cm 38.2pt 0pt 0cm; TEXT-ALIGN: justify"><FONT=20
face=3D"Times New Roman" size=3D3>Pessoal, como resolvo =
esta:</FONT></P>
<P style=3D"MARGIN: 0cm 38.2pt 0pt 0cm; TEXT-ALIGN: justify"><FONT=20
face=3D"Times New Roman" size=3D3></FONT> </P>
<P style=3D"MARGIN: 0cm 38.2pt 0pt 0cm; TEXT-ALIGN: justify"><FONT=20
face=3D"Times New Roman" size=3D3>Um grupo de 8 jovens pretende sair =
para um=20
passeio em dois carros (cada um com capacidade para 4 pessoas). =
Apenas 4=20
delas dirigem. O n=BA de modos deles escolherem seus lugares nos =
dois carros =E9=20
igual a : </FONT></P>
<P style=3D"MARGIN: 0cm 38.2pt 0pt 0cm; TEXT-ALIGN: justify"><FONT=20
face=3D"Times New Roman" size=3D3></FONT> </P>
<P style=3D"MARGIN: 0cm 38.2pt 0pt 0cm; TEXT-ALIGN: justify"><FONT=20
face=3D"Times New Roman" size=3D3>a) 10.080.<SPAN> =
</SPAN>b)=20
8.640.<SPAN> </SPAN>c) 4.320.<SPAN> =
</SPAN>d)=20
1.440.<SPAN> </SPAN>e) 720.</FONT></P>
<P style=3D"MARGIN: 0cm 38.2pt 0pt 0cm; TEXT-ALIGN: justify"><FONT=20
face=3D"Times New Roman" size=3D3></FONT> </P>
<P style=3D"MARGIN: 0cm 38.2pt 0pt 0cm; TEXT-ALIGN: justify"><FONT=20
face=3D"Times New Roman" size=3D3>Desde j=E1=20
=
obrigado </FONT></P></DIV></DIV></BLOCKQUOTE></DIV><BR></BLOCKQUOTE>=
</BODY></HTML>
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