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Re: [obm-l] teoria dos números - simples
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] teoria dos números - simples
- From: "saulo nilson" <saulo.nilson@xxxxxxxxx>
- Date: Wed, 21 Mar 2007 22:10:41 -0300
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M=10*q1+5
M=16*q2+11
M=24*q3+19
24q3+8=16q2
3q3+1=2q2
24q3+14=10q1
16q2+6=10q1
3q3+1=2q2
12q3+7=5q1
8q2+3=5q1
sistema acima e SPD a 1a equaçao e CL de 2 e 3
24q3+8=10q1-6
24q3=10q1-14
q3=(5q1-7)/12
omenor valor de q1 que torna q3 inteiro positivo
5q1-7=48
q1=11
M=116
On 3/21/07, Emanuel Valente <emanuelvalente@gmail.com> wrote:
Travei nessa questão. Agora é com vocês, cabeças.
Determinar o menor número que dividido por 10; 16 e 24 deixa,
respectivamente os restos 5; 11 e 19.
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