[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
Re: [obm-l] UFCG - 2007
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] UFCG - 2007
- From: "saulo nilson" <saulo.nilson@xxxxxxxxx>
- Date: Thu, 22 Feb 2007 21:16:55 -0300
- DKIM-Signature: a=rsa-sha1; c=relaxed/relaxed; d=gmail.com; s=beta; h=domainkey-signature:received:received:message-id:date:from:to:subject:in-reply-to:mime-version:content-type:references; b=XQ3vX/U0Qtd9z+O2u5cLlAmWXOBNVHDv0LU7TpqrlgQRUaA2aog2fJh4HTLnm8/o9Wahdf1KtMAfP0OyZ8uKyiXoAAeRhhYp+BAXChDRGYrIkpsLN2VWKMfyJW22w2/3IlH5KzzyUA0ZoiKPbLnsjxx2bPN8ILuGGOv9CkzQN4w=
- DomainKey-Signature: a=rsa-sha1; c=nofws; d=gmail.com; s=beta; h=received:message-id:date:from:to:subject:in-reply-to:mime-version:content-type:references; b=NKXDGMBa+FLh6gOLg/pLmVX9uSEItzXfqYKjHl718Jbo4HC8/L9xR4Ie3Pf1/3MBzJYENXHLAT2KOej3VwHm5t6k6QI4UGCVsRWb7vgUSIEKagMQhn2lAH1Bx0rJzY9UzFYc1OLmkXDH+foLiwUKchrhlGFsNFJg/0w0s3IFHqw=
- In-Reply-To: <e67373650701220651r3bb7d32dt4cc94c4d28df9042@mail.gmail.com>
- References: <69816.73565.qm@web30109.mail.mud.yahoo.com> <e67373650701220651r3bb7d32dt4cc94c4d28df9042@mail.gmail.com>
- Reply-To: obm-l@xxxxxxxxxxxxxx
- Sender: owner-obm-l@xxxxxxxxxxxxxx
usa lei dos cossenos que vc acha o angulo e so fazer o desenho.
On 1/22/07, Marcelo Costa <mat.moura@gmail.com> wrote:
Ajuda URGENTE!
Agarrei neste problema, por favor me ajudem.
Obrigado!
Em um triângulo ABC, tem-se que os ângulos ABC = ACB = 80º. Se P é um ponto sobre o lado AB tal que AP = BC, a medida do ângulo BPC é igual a: