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[obm-l] Re: [obm-l] Re:[obm-l] Triângulos



6*(3)^1/2 é o lado do triangulo equilátero, a área será  27*(3)^1/2.
 
 
Cláudio Thor
----- Original Message -----
To: obm-l
Sent: Thursday, June 22, 2006 2:58 PM
Subject: [obm-l] Re:[obm-l] Triângulos

Bom Dia!!!!!
A resposta é seis raiz de três, 6*(3)^1/2 
Abraços,
Giuliano Pezzolo Giacaglia
(Stuart)