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Re: [obm-l] Mais uma questão legal

2005! < 2006^2005 <==> (2005!) * (2005!)^2005 < 2006^2005 * 2005!^2005 = (2006*2005!)^2005 = (2006!)^2005 <==> (2005!)^2006 < (2006!)^2005 <==> (2005!)^(1/2005) < (2006!)^(1/2006)

On 12/5/05, Marcos Martinelli <mffmartinelli@gmail.com > wrote:
   Provar que (2005!)^(1/2005)<=(2006!)^(1/2006).



--
Bruno França dos Reis
email: bfreis - gmail.com
gpg-key: http://planeta.terra.com.br/informatica/brunoreis/brunoreis.key
icq: 12626000

e^(pi*i)+1=0