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Re: [obm-l] desigualdade

To: obm-l@xxxxxxxxxxxxxx
Subject: Re: [obm-l] desigualdade
From: Júnior <jssouza1@xxxxxxxxx>
Date: Mon, 12 Sep 2005 23:05:02 -0300
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Um amigo resolveu de uma forma tao simples...
Vejam se procede a demonstração:

Mostre que ln 2 > (2/5)^(2/5).

log 2 (na base 2) = 1 > ln 2 "evidente"
1 > ln 2 > (2/5)^(2/5)
1 > (2/5)^(2/5)
5^(2/5) > 2^(2/5) . FIM.

Júnior.

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