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Re: [obm-l] Trigonometria

To: obm-l@xxxxxxxxxxxxxx
Subject: Re: [obm-l] Trigonometria
From: "Augusto Cesar de Oliveira Morgado" <morgado@xxxxxxxxxxxxxxx>
Date: Thu, 1 Jul 2004 22:44:03 -0200
In-Reply-To: <006a01c45f34$28a708b0$2d00b8c8@rafael>
References: <5b.5277e6e1.2e14f079@aol.com> <006a01c45f34$28a708b0$2d00b8c8@rafael>
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cos 3x = sen 2x
cos 3x = cos (pi/2 - 2x)
3x + pi/2 - 2x = 2kpi ou 3x -pi/2 +2x = 2kpi 
x = 2kpi - pi/2  ou  x = 2kpi/5 + pi/10
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References:
- [obm-l] Trigonometria
  - From: Korshinoi
- Re: [obm-l] Trigonometria
  - From: Rafael

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