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RE: [obm-l] AJUDA COM LIMITES



Carissimo Gabriel,

 

1)     lim (x->3) (raiz(x^2+16) – 5) (raiz(x^2+16) +5)/((x^2-3x) (raiz(x^2+16) + 5)) = lim(x->3) (x^2-9)/ )/((x^2-3x) (raiz(x^2+16) + 5))  =

= lim(x->3)(x+3)(x-3)/x(x-3) raiz(x^2+16) + 5) = lim(x->3) (x+3)/x raiz(x^2+16) + 5) = 6/3(5) = 3/5.  

 

 

2)     lim(x->00) raiz(x+1)/raiz(9x+1) = lim(x->00) raiz(x)*raiz(1+1/x) / raiz(x)*raiz(9+1/x) = raiz(1+1/x)/raiz(9+1/x) = 1/9

 

 

3)     lim(x->0) (1-cosx)(1+cosx)/x^2(1+cosx) = lim(x->0) (sinx)^2/(x^2*(1+cosx)) = lim(x->0) ((sin x)/x)^2 * 1/(1+cosx) = ½

 

 

Acho que os resultados sao esses caro amigo.

 

Leandro.

 

 

-----Original Message-----
From: owner-obm-l@sucuri.mat.puc-rio.br [mailto:owner-obm-l@sucuri.mat.puc-rio.br] On Behalf Of Afemano
Sent:
Tuesday, March 11, 2003 12:00 PM
To: obm-l@mat.puc-rio.br
Subject: [obm-l] AJUDA COM LIMITES

 

Olá, alguém pode me ajudar com esse problemas "simples" ??

 

1)  lim(x-> -3)  (raiz(x^2 + 16) - 5 )/ ( x^2 - 3x )

 

2) lim(x-> +00)  ( raiz(x + 1) ) / ( raiz(9x + 1) )

 

3) lim(x-> 0) ( 1 - cosx ) / x^2

 

Valeu ae !!

gabriel