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[obm-l] função zeta
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Subject
: [obm-l] função zeta
From
: "Wagner" <
timpa@xxxxxxxxxx
>
Date
: Wed, 12 Feb 2003 22:53:11 -0300
Organization
: Wagner
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obm-l@xxxxxxxxxxxxxx
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Oi para todos!
Porquê zeta( 0 ) = -1/2 ?
infinito
Se zeta( x ) = SOMATÓRIO 1/(n^x) , zeta( 0 ) não deveria ser igual a infinito ?
n = 1
André T.
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