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Re: =?x-user-defined?Q?Demonstra=E7=E3o?=



a^2 + b^2 + c^2 = a.b + a.c + b.c 
2a^2 +2 b^2 + 2c^2 -2 a.b -2 a.c -2 b.c = 0
(a~b)^2 + (b-c)^2+ (c-a)^2 = 0
a=b=c
"João Paulo Paterniani da Silva" wrote:
> 
>    Olá.
>    Mostre que se a^2 + b^2 + c^2 = a.b + a.c + b.c , então a=b=c.
> 
> João Paulo Paterniani da Silva
> 
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