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Re: Ajuda

At 19:02 02/10/00 EDT, you wrote:
>
>   Olá.
>   Por favor, me ajudem nesse exercício:
>
>  (FATEC)-Seja n pertencente IN, tal que
>
>   (1+2+3+...+n)/(n+1)! = 1/240

Entao n(n+1) / 2(n+1)! = 1/240 -> 1/2(n-1)! = 1/240 -> (n-1)!=120 -> n=6...

Bruno Leite
>
>   Então o valor de log  (2n+4) é:
>                       1/2
>
>  a)-4   b)4   c)-2sqrt2   d)2sqrt2    e)1/2
>
>
>    Muito obrigado.
>
>
>
>
>João Paulo Paterniani da Silva
>
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