Re: Second problem

["Luis Lopes" <llopes@xxxxxxxxxxxxx>]

Dear Cecil,

I have been having problems to send a message to you.
Hope this one will follow.

Well, I don't know. I have to send the problem to the list
again. I just transcribed it to LaTeX to facilitate reading.

Many thanks,
Luis

-----Mensagem Original----- 
De: <ccrousse@memphis.edu>
Para: Luis Lopes <llopes@ensrbr.com.br>
Enviada em: Sexta-feira, 4 de Agosto de 2000 14:27
Assunto: Second problem


> 
> Dear Luis:
> 
>    Is it possible that the second problem actually reads
> 
>  \left\lfloor \frac{m^2 x-13}{1999} \right\rfloor = \frac{x-12}{2000} ?
> 
> For m = \pm 1 this equation has 1999 solutions, namely
> 
> x = 2000k + 12,   k = 1,2,\ldots,1999.
> 
> For the given equation to have 1999 solutions seems to be out of
> the question.
> 
>