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=?UTF-8?Q?Re:_[obm-l]_Equa=C3=A7=C3=A3o_diferencial?=
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- Subject: =?UTF-8?Q?Re:_[obm-l]_Equa=C3=A7=C3=A3o_diferencial?=
- From: "Felipe Diniz" <edward.elric.br@xxxxxxxxx>
- Date: Sat, 22 Sep 2007 13:20:14 -0300
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dy/dx = y/x + x sqrt(y/x)
u= y/x -> y=ux -> dy/dx = x du/dx +u
assim
x u' +u = u + x sqrt(u)
u'=u^1/2
u^(-1/2) du= dx
2 u^1/2 = x+C
y/x = (x/2+C)^2
y= x(x/2 +C)^2
On 9/22/07, Daniel S. Braz <dsbraz@gmail.com> wrote:
Senhores,
Alguém pode, por favor, me dar uma dica nessa eq. diferencial?
dy/dx = y/x + sqrt(xy)
obrigado.
Daniel.
-- "O modo mais provável do mundo ser destruído, como concordam a maioriados especialistas, é através de um acidente. É aí que nós entramos.Somos profissionais da computação. Nós causamos acidentes" - NathanielBorenstein
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