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Re: [obm-l] Ajuda
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] Ajuda
- From: "Marcelo Salhab Brogliato" <msbrogli@xxxxxxxxx>
- Date: Sun, 22 Jul 2007 01:56:23 -0300
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Olá Marcelo,
x^4 = (x-1)^2
x^2 = |x-1|
se x>1, temos: x^2 = x-1 ... x^2-x+1=0 ... nao tem raizes reais
se x<1, temos: x^2 = -x+1 ... x^2+x-1=0 ... x=(-1-sqrt(5))/2
(2x+1)^2 = (-1-sqrt(5)+1)^2 = (-sqrt(5))^2 = 5
letra C
abracos,
Salhab
On 7/21/07, Marcelo Costa <mat.moura@gmail.com> wrote:
> Alguém poderia me ajudar??
>
> Sabendo-se que x^4 = (x - 1)^2, então o valor de (2x + 1)^2 vale:
> a) 3
> b) 4
> c) 5
> d) 6
> e) 7
>
> Valeu!!!
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