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Re: [obm-l] INTEGRAL

To: obm-l@xxxxxxxxxxxxxx
Subject: Re: [obm-l] INTEGRAL
From: "saulo nilson" <saulo.nilson@xxxxxxxxx>
Date: Mon, 28 May 2007 22:30:32 -0300
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i(n+2)-i(n)=int(sen(n+2)x-sennx)/sin(x) dx

=intsenx*cos(x(n+1))/senx dx (0 a pi)

i(n)=i(n+2)

i(1331)=i(1)=pi

On 5/28/07, Klaus Ferraz <klausferraz@yahoo.com.br> wrote:

Considere I_n=int{0,pi}sin(nx)/sin(x)dx. Calcule I_(n+2) - I_n e, em seguida, determine I_1331.

vlw.

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References:
- [obm-l] INTEGRAL
  - From: Klaus Ferraz

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