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Re: [obm-l] equação do terceiro grau
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] equação do terceiro grau
- From: "saulo nilson" <saulo.nilson@xxxxxxxxx>
- Date: Tue, 15 May 2007 05:14:56 -0300
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tantando uma soluçao da forma
x=rqa+b
temos
8*(a^2rqa+3a*b+3rqa*b^2+b^3)-6rqa-6b-1=0
agrupando termos semlhantes
rqa(8a^2+24b^2-6)+24ab+8b^3-1=0
8a^2+24b^2-6=0
24ab+8b^3-1=0
16a^2b-144ab-6b+6=0
8a^2b-72ab-3b+3=0
fazendo b=1/2 porque a raiz esta em torno dos extremos
4a^2-36a+3/2=0
delta=1272
a=(72+-4rq318)/16