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Re: [obm-l] arctg^2
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] arctg^2
- From: "Marcelo Salhab Brogliato" <msbrogli@xxxxxxxxx>
- Date: Wed, 11 Apr 2007 18:17:11 -0300
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Ola,
como a funcao eh real, temos que ter:
3 - (arctgx)^2 >= 0
|arctgx| <= sqrt(3)
-sqrt(3) <= arctgx <= sqrt(3)
-pi/3 <= x <= pi/3
abracos,
Salhab
On 4/11/07, vitoriogauss <vitoriogauss@uol.com.br> wrote:
> Questão da prova para professor da marinha:
>
> O dominio da função real f(x) = sqrt[3 - arctg^2 x]
>
> eu achei o valor igual ao Steiner :[-pi/3,pi/3]
>
>
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