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Re: [obm-l] Demonstrar por pif...
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] Demonstrar por pif...
- From: "saulo nilson" <saulo.nilson@xxxxxxxxx>
- Date: Tue, 27 Mar 2007 21:50:24 -0300
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n=1
S1=0mod6
supondo que
Sn e divisivel por 6 dai
para n+1
Sn+1 = (n+1)(n^2+2n+6)=n*(n+1)(n+2)+6*(n+1)
=n^3+2n^2+6n+n^2+2n+6+6k1
=6k2+3n^2+3n+6(k3)
=6k4+3n(n+1)
n*(n+1) e multiplo de 2
Sn+1=6k4+6k5=6k6 multiplo de 6