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Re: [obm-l] vetor normal
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] vetor normal
- From: "saulo nilson" <saulo.nilson@xxxxxxxxx>
- Date: Sat, 24 Mar 2007 22:04:56 -0300
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f(x,y)=4x+4y+2z=0
de forma que um vetor r[3]=i+j+k e normal ao plano acima
r[3]/3 e o vetor unitario.
On 3/24/07, vitoriogauss <vitoriogauss@uol.com.br> wrote:
Sejam f:R2->R uma funç~so linear,
i = (1,0,0)
j = (0,1,0)
k = (0,0,1)
Suponha que f(i)=4, f(j)=4 e f(k)=
2.Um vetor unitario, normal ao plano f_-1(0) é
a)(r[3]/3,r[3]/3,r[3]/3,)
b)(r[11]/11,r[11]/11,r[11]/11)
c)(2/7,3/7,6/7)
d)(2/3,2/3,1/3)
e)(4/5,3/5,0)
Vitório Gauss
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