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Re: [obm-l] UFCG - 2007
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] UFCG - 2007
- From: "saulo nilson" <saulo.nilson@xxxxxxxxx>
- Date: Thu, 22 Feb 2007 21:18:37 -0300
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o triangulo e isosceles de base x, e lados y, vc tem os angulos, e so achar o valor de x em funçao de yai vc vai ter o AP que e igual a x, usa a lei dos cossenos nos triangulos e pronto.
On 2/22/07, saulo nilson <saulo.nilson@gmail.com> wrote:
usa lei dos cossenos que vc acha o angulo e so fazer o desenho.
On 1/22/07, Marcelo Costa <mat.moura@gmail.com
> wrote:
Ajuda URGENTE!
Agarrei neste problema, por favor me ajudem.
Obrigado!
Em um triângulo ABC, tem-se que os ângulos ABC = ACB = 80º. Se P é um ponto sobre o lado AB tal que AP = BC, a medida do ângulo BPC é igual a: