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Re: [obm-l] binomio
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Subject
: Re: [obm-l] binomio
From
: "Johann Peter Gustav Lejeune Dirichlet" <
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>
Date
: Mon, 15 May 2006 12:47:54 -0300
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Temos que resolver esta eq diofantina aqui:
28=20a+5b
O que me parece impossivel (modulo 5 é impossível).
Entao a resposta e: 0
Em 11/05/06,
Marcus Aurelio
<
marcusaurelio80@globo.com
> escreveu:
Determine o coeficiente x^28 em (x+2)^20(x-1)^5
--
Ideas are bulletproof.
V
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[obm-l] binomio
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