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Re: [obm-l] Combinatoria

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Subject: Re: [obm-l] Combinatoria
From: Davi de Melo Jorge Barbosa <dbarbosa@xxxxxxxxx>
Date: Fri, 11 Nov 2005 21:32:59 -0200
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numero de conjuntos com 6 elem. + n. de conj. com 7 elem. + n. de
conj. com 8 elem. =
C(8,6) + C(8,7) + C(8,8) = 8!/(2!6!) + 8!/(1!7!) + 8!/(0!8!) = 28 + 8 + 1 = 37

On 11/11/05, Robÿffffe9rio Alves <prof_roberio@yahoo.com.br> wrote:
> Dado um conjunto com oito elementos. Quantos subconjuntos podemos com pelo
> menos seis elementos ?
>
>  ________________________________
>  Yahoo! Acesso Grátis: Internet rápida e grátis.
> Instale o discador agora!
>
>

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References:
- [obm-l] Combinatoria
  - From: Robÿffffe9rio Alves

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