[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

Re: [obm-l] Intervalo

To: obm-l@xxxxxxxxxxxxxx
Subject: Re: [obm-l] Intervalo
From: Adroaldo Munhoz <amunhoz@xxxxxxxxx>
Date: Tue, 18 Oct 2005 15:34:20 -0200
DomainKey-Signature: a=rsa-sha1; q=dns; c=nofws; s=beta; d=gmail.com; h=received:message-id:date:from:user-agent:x-accept-language:mime-version:to:subject:references:in-reply-to:content-type:content-transfer-encoding; b=HPXN6KY7Jgcz2c1odXVCXt2Z3nXgWpzvUzEcg79S3yLJH9KL8qLNYjeVk+tVD0Un0ojDZ+ZGyvoowE+80g2GBJESVM6OQv1N5D52SSsZpywFhscZYaW7p6QYm91Rp1Tdwi7YD9QDZIPim62PZPQJ/F1PMx5TmtJ3vA729Suuhpk=
In-Reply-To: <000c01c5d405$ba5b7c90$0401a8c0@claudiaipkr15f>
References: <000c01c5d405$ba5b7c90$0401a8c0@claudiaipkr15f>
Reply-To: obm-l@xxxxxxxxxxxxxx
Sender: owner-obm-l@xxxxxxxxxxxxxx
User-Agent: Mozilla Thunderbird 1.0.6 (Windows/20050716)

Title:

log2(senx)=log2(cosx+senx)
senx>0
cosx+senx>0
senx=cosx+senx=>cosx=0 e senx>0 => x=pi/2

Anna Luisa wrote:

Por favor me alguem me dah uma maozinha!

- Dada a equação log2 (senx) - log2 (cosx + senx) = 0

Determine:

a) cos x.

b) a menor raiz no intervalo [ - 2pi , 2pi].

Obrigada,

Anninha.

========================================================================= Instruções para entrar na lista, sair da lista e usar a lista em http://www.mat.puc-rio.br/~nicolau/olimp/obm-l.html =========================================================================

Follow-Ups:
- Re: [obm-l] Intervalo
  - From: Luiz Miletto

References:
- [obm-l] Intervalo
  - From: Anna Luisa

Prev by Date: [obm-l] Intervalo
Next by Date: Re: [obm-l] Intervalo
Prev by thread: [obm-l] Intervalo
Next by thread: Re: [obm-l] Intervalo
Index(es):
- Date
- Thread