Re: [obm-l] Duvidas

["Renan Machado" <renankmachado@xxxxxxxxx>]

19992*19992 - (19992-2)(19992+2) = 19992^2- (19992^2 - 2^2) = 4

----- Original Message -----
From: matduvidas48

To: "obm-l"
Subject: [obm-l] Duvidas
Date: Fri, 8 Apr 2005 21:24:24 -0300

 19992. 19992 – 19990. 19994 =

 

a) 0                 b) 4                c) 14             d) 24          e) 104

 

 

 

 

 

 

Se 219. 654 = P e 220. 654 = P + Q , então Q é igual a :

 

a) 7/8             b) 8/7          c) 6/5         d) 3/2          e) ndr

 

 

 

Agradeço desde de já.

--

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