qual é a derivada destas funcoes .Achar os pontos maximos e
minimos.
f(x)=exp(x^3-x)
f'(x)=exp(x^3-x)*(3*x^2-1)
min=0 / min=0,68052 max=1,4697
max=[inf]
f(x) sobe de 0 a 1,4697, desce até 0,68052 e
sobe ao infinito.
f(x)=x*sqr(x-x^2) sqr=raiz quadrada
f'(x)=sqr(x-x^2) +
x/[2*sqrt(x-x^2)]*(1-2*x)
min=0 max=0,32476
f(x)=(cos x )/(2+sen x)
f'(x)=[ (-sen x)*(2+sen x ) - (cos x)^2 ] /
(2+sen x )^2
min=-0,57735 max=+0,57735
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