[obm-l] Re: Polinomial do 2� grau

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Subject: [obm-l] Re: Polinomial do 2� grau
From: "J�nior" <jssouza1@xxxxxxxxx>
Date: Wed, 22 Mar 2006 12:33:28 -0300
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Usei a mesma letra pra duas situa��es.. agora ta certo.
f(x)= ax^2 + bx + c ; a > 0
0 < b < 1
Mostrar f[bx_1 + (1-b)x_2] < bf(x_1) + (1-b)f(x_2).

Em 22/03/06, J�nior <jssouza1@gmail.com> escreveu:

Sendo f(x)= ax^2 + bx + c e al�m disso 0 < a < 1, mostre que f[ax_1 + (1-a)x_2] < af(x_1) + (1-a) f(x_2).

J�nior.