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[obm-l] Re: [obm-l] Equa��o Trigonom�trica



Caro Augusto
 
    Na passagem:
 
    sena sen20 = sen80 sen80 cosa - (1/2) sen160 sena
    sena sen20 = sen80 sen80 cosa - (1/2) sen20 sena
 
     N�o seria cos20 no lugar de sen20, o que compromete a resolu��o.
 
 
----- Original Message -----
Sent: Thursday, June 20, 2002 9:42 PM
Subject: Re: [obm-l] Equa��o Trigonom�trica

sena sen20 = sen 80 sen(80-a)
sena sen20 = sen80 [sen80 cosa - sena cos 80]  
sena sen 20 = sen80 sen80 cosa - sen80 cos80 sena
sena sen20 = sen80 sen80 cosa - (1/2) sen160 sena
sena sen20 = sen80 sen80 cosa - (1/2) sen20 sena
 (3/2) sena sen20 = (1/2) (1-cos160) cosa
3 sena sen20 = (1+cos20) cosa
tana = (1/3) [(1+cos20)/sen20] = (1/3) [2 sen10 sen10 / 2 sen10 cos10] = (1/3) tan10
a = arctan [(1/3) tan10] + k180 = 3,36 + k180 aproximadamente

Caio H. Voznak wrote:
000c01c2172d$138a67c0$e811ccc8@e9i5z1" type="cite">
No desenvolvimento de um exerc�cio cheguei a seguinte equa��o:
 
{[sen(a)]/[sen(80�-a)]} = [sen(80�)]/[sen(20�)]
 
sendo "a" diferente de 80�
 
ser� que alguem poderia me ajudar a desenvolver essa equa��o.
 
Um abra�o
 
Caio Voznak 
 

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