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Re: [obm-l] PA - do Iezzi
- To: obm-l@xxxxxxxxxxxxxx
- Subject: Re: [obm-l] PA - do Iezzi
- From: "saulo nilson" <saulo.nilson@xxxxxxxxx>
- Date: Mon, 16 Apr 2007 21:05:54 -0300
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a=a1+(p-1)r
b=a1+(q-1)r
A(p+q)=a1+(p+q-1)r=a+b-a1+r
a-b=r(p-q)
r=(a-b)/(p-q)
a+b=2a1+r(p+q-2)
a1=((a+b)(p-q)-(a-b)(p+q-2)/2(p-q)
a1=(-2aq+2bp+2(a-b))/2(p-q)
a1=(a(1-q)-b(1-p))/(p-q)
On 4/16/07, Emanuel Valente <emanuelvalente@gmail.com> wrote:
Na PA em que Ap = a e Aq = b com p !=q,
calcular o termo Ap+q.
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