Re: [obm-l] Retas no R3

entendi...apesar de eu ter feito diferente em rela��o a distancia de r a s:

Eu fiz:

Seja P=(0,29,0), com $P\in r$ ,e Q=(0,0,0), com $Q\in r$ , ent�o

PQ=(0,-29,0). A dist�ncia entre r e s ser� dada por:

$d=\left|\\\begin{array}\\PQ *(v x u)\\\\\end{array}\right|\div \left|\\\begin{array}(v x u) \\\\\end{array}\right|$

como:

$v x u = \left(\\\begin{array}\\i & j & k \\\\3 & -2 & 3 \\\\1 & 2 & 1 \\\\\end{array}\right)= (-4,6,8)$

e |PQ * (v x u)| = 6*29 e |(v x u)| = $\2sqrt{29}$ , logo

d = $\6*29\div 2sqrt{29}$ = $\3sqrt{29}$